how many bulbs of resistance 6 ohm should be joined in parallel to draw a current of 2 amperes from a battery of 3 volts.?

**Solution:**

Suppose n resistances of 6 ohm are connected in parallel and the resultant resistance=R

Then,

1/R=n/6=>R=6/n

Now Current I=2 A,Voltage V=3 volts

By ohm's law V=IR

3=2x6/n

n=4

Hence 4 bulbs are connected in parallel.

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